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标题:
ADMP输出结果中参数的单位是什么
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作者Author:
diaolanxinyu
时间:
2015-1-27 16:40
标题:
ADMP输出结果中参数的单位是什么
ADMP输出结果中参数的单位是什么? 谢谢大家!
#p PM6 admp=(stepsize=1000,maxpoint=2000) (体系就只有6个原子,CH4O)
参数:General parameters:
Maximum Steps = 2000
Random Number Generator Seed = 398465
Time Step = 0.10000 femtosec
Ficticious electronic mass = 0.10000 amu
MW individual basis funct. = True
Initial nuclear kin. energy = 0.10000 hartree
NKE,为什么一般只用NKE不用DKE呢?
Initial electr. kin. energy = 0.00000 hartree
DKE
Initial electr. KE scheme = 0
Multitime step - NDtrC = 1
Multitime step - NDtrP = 1
No Thermostats chosen to control nuclear temperature
Integration parameters:
Follow Rxn Path (DVV) = False
Constraint Scheme = 10
Projection of angular mom. = True
Rotate density with nuclei = True
第一步输出:
ADMP step 0
GnVelC Random: Velocity
----------随机速度,是原子初始的笛卡尔速度吗?单位是什么?
I= 1 X= 6.776577902369D-01 Y= 7.429033107124D-01 Z= 8.096585665196D-01
I= 2 X= 5.918403073752D-01 Y= 3.410950604214D-01 Z= 2.852121111959D-01
I= 3 X= 1.912162494242D-01 Y= 7.195232935778D-01 Z= 5.673842562704D-01
I= 4 X= 4.035037873473D-02 Y= 3.464603346208D-01 Z= 5.858358356755D-01
I= 5 X= 6.576648108690D-01 Y= 9.959465304093D-02 Z= 8.182893439322D-01
I= 6 X= 8.670178057043D-01 Y= 3.534648908784D-01 Z= 7.267570405295D-01
GnVelC Scaled: Velocity
----------
单位和含义是什么?
I= 1 X= 1.190813188988D-01 Y= 1.305465787134D-01 Z= 1.422771365547D-01
I= 2 X= 1.040010539170D-01 Y= 5.993888102527D-02 Z= 5.011885771320D-02
I= 3 X= 3.360144825955D-02 Y= 1.264381285246D-01 Z= 9.970351781167D-02
I= 4 X= 7.090564569647D-03 Y= 6.088169307159D-02 Z= 1.029459189808D-01
I= 5 X= 1.155680554403D-01 Y= 1.750125625390D-02 Z= 1.437937786891D-01
I= 6 X= 1.523565807101D-01 Y= 6.211256772466D-02 Z= 1.277092776798D-01
GnVelC MW: Velocity
----------是原子
初始的质量加权笛卡尔速度吗,
单位是什么?
I= 1 X= -2.360253685914D-02 Y= -2.566643445779D-02 Z= -9.340270737142D-03
I= 2 X= 6.305375248492D-02 Y= 2.001113793989D-02 Z= 6.179772153078D-03
I= 3 X= -7.882946007422D-03 Y= 8.161870853846D-02 Z= 5.538465026683D-02
I= 4 X= -3.246039644181D-02 Y= 1.271346846427D-02 Z= 6.355939627588D-02
I= 5 X= 7.215022791778D-02 Y= -3.066696835342D-02 Z= 9.568191225855D-02
I= 6 X= -3.367903429401D-03 Y= 1.227205833397D-03 Z= -4.733559982057D-02
GnVelC Scaled: Velocity
----------
单位和含义是什么?
I= 1 X= -5.221249413169D-02 Y= -5.677815764071D-02 Z= -2.066213619163D-02
I= 2 X= 1.394847384944D-01 Y= 4.426775937225D-02 Z= 1.367062020509D-02
I= 3 X= -1.743830650957D-02 Y= 1.805533178926D-01 Z= 1.225194878119D-01
I= 4 X= -7.180746158116D-02 Y= 2.812417586915D-02 Z= 1.406033014533D-01
I= 5 X= 1.596075614346D-01 Y= -6.784011882900D-02 Z= 2.116633187409D-01
I= 6 X= -7.450327864891D-03 Y= 2.714770778965D-03 Z= -1.047137323671D-01
Frobenius norm of [F,P] = 2.123691D-15
----------
是描述什么的?
单位
是什么?
Current gradient on entry to l121
----------
是描述什么的?单位
是什么?
I= 1 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= -6.168848482799D-03
I= 2 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= 2.765958500766D-03
I= 3 X= 7.689313016146D-06 Y= 0.000000000000D+00 Z= 1.182340274514D-03
I= 4 X= -3.844451335416D-06 Y= -6.657904818963D-06 Z= 1.182340449645D-03
I= 5 X= -3.843954723276D-06 Y= 6.658191538667D-06 Z= 1.182340449645D-03
I= 6 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= -1.441311917709D-04
作者Author:
diaolanxinyu
时间:
2015-1-27 16:51
再补充一点
Summary information for step 0
Time (fs) 0.000000
EKinC = 0.1000000; EKinPA = 0.0000000; EKinPB = 0.0000000
EKin = 0.1000000; EPot = 0.0424303; ETot = 0.1424303
ETot-EKinP = 0.1424303
Integrand for the Velocity-Velocity Auto-Correlation Function = 1.875165884684D-01
Angular momentum
JX = 0.5354349475D-13 JY = -0.6119176536D-13 JZ = -0.7359657037D-14
Jtot = 0.8164252893D-13 H-BAR; J (Quantum Number) = 0.0000000000D+00
Total energy 1.424302843D-01 A.U.
Total angular momentum 8.164253D-14 h-bar
Tr(PA)-NA = -4.441D-15
Tr(PA**2-PA) = -6.217D-15
Tr[(PA**2-PA)**2] = 2.116D-16
Tr(PB)-NB = 3.553D-15
Tr(PB**2-PB) = 3.553D-15
Tr[(PB**2-PB)**2] = 1.989D-16
Cartesian coordinates: ----------跟初始坐标差别挺大的,原因是什么?
I= 1 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= 5.742058886893D+00
I= 2 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= 3.693509644025D+00
I= 3 X= -1.931390739074D+00 Y= 0.000000000000D+00 Z= 6.424908628216D+00
I= 4 X= 9.656953695372D-01 Y= 1.672633449877D+00 Z= 6.424908628216D+00
I= 5 X= 9.656953695372D-01 Y= -1.672633449877D+00 Z= 6.424908628216D+00
I= 6 X= 0.000000000000D+00 Y= 0.000000000000D+00 Z= -5.755121020403D+00
MW Cartesian velocity--------------------感觉这个才是是原子初始的质量加权笛卡尔速度?不确定,单位是?
I= 1 X= -5.221249413169D+13 Y= -5.677815764071D+13 Z= -2.066213619163D+13
I= 2 X= 1.394847384944D+14 Y= 4.426775937225D+13 Z= 1.367062020509D+13
I= 3 X= -1.743830650957D+13 Y= 1.805533178926D+14 Z= 1.225194878119D+14
I= 4 X= -7.180746158116D+13 Y= 2.812417586915D+13 Z= 1.406033014533D+14
I= 5 X= 1.596075614346D+14 Y= -6.784011882900D+13 Z= 2.116633187409D+14
I= 6 X= -7.450327864891D+12 Y= 2.714770778965D+12 Z= -1.047137323671D+14
作者Author:
sobereva
时间:
2015-1-28 01:26
MW就是质权。
凡是量化程序里没写单位的情况,一般都是a.u.。所以坐标也是,看看和你输入的坐标是不是相差0.5292倍数。
Scaled就是给所有随机生成的速度统一乘上一个倍数,目的大抵是让实际速度和所设的核动能相对应。
我没仔细看过ADMP的原理,但核动能显然是主导体系运动的关键,所以只默认设了NKE,电子密度的动能应该是随着模拟的进行自发地调整的。
作者Author:
diaolanxinyu
时间:
2015-1-28 17:06
1#的数据应该是比例因子参数,就是您说的那样。
2#的Cartesian coordinates跟初始坐标没有看出来是0.5292的倍数,0.5292您是怎么得到的?
这是初始坐标
C 0.00000000 0.00000000 6.08404557
H 0.00000000 0.00000000 5.00000000
H -1.02204796 0.00000000 6.44539409
H 0.51102398 0.88511950 6.44539409
H 0.51102398 -0.88511950 6.44539409
O 0.00000000 0.00000000 0.00000000我把2#的Cartesian coordinates保存成gjf文件后查看,感觉像是把初始坐标拉伸了,见附件!
关于2#的
MW Cartesian velocity
I= 1 X= -5.221249413169D+13 Y= -5.677815764071D+13 Z= -2.066213619163D+13
I= 2 X= 1.394847384944D+14 Y= 4.426775937225D+13 Z= 1.367062020509D+13
I= 3 X= -1.743830650957D+13 Y= 1.805533178926D+14 Z= 1.225194878119D+14
I= 4 X= -7.180746158116D+13 Y= 2.812417586915D+13 Z= 1.406033014533D+14
I= 5 X= 1.596075614346D+14 Y= -6.784011882900D+13 Z= 2.116633187409D+14
I= 6 X= -7.450327864891D+12 Y= 2.714770778965D+12 Z= -1.047137323671D+14
这一部分应该就是初始的每个原子的
质量加权笛卡尔速度,因为对于氧来说,若沿坐标轴的运动速度是0.5埃/飞秒,约为4.01×10^15 amu^1/2 *Bohr/秒,
2#的
MW Cartesian velocity中的原子速度大概为0.01~0.1
埃/飞秒之间。
如若不是的话,如何手动添加每个原子(如甲烷)在每个轴上的
质量加权笛卡尔速度?有什么规则吗?
作者Author:
sobereva
时间:
2015-1-28 23:48
0.5292就是波尔和埃的转换因子。很明显你的图中键长的变化就是因为单位转换问题。输出数据中没看到比例关系大抵是高斯自动调整了朝向。
作者Author:
diaolanxinyu
时间:
2015-1-29 10:06
谢谢sobereva老师!
2#的MW Cartesian velocity
这一部分应该就是初始的每个原子的质量加权笛卡尔速度, 单位是amu^1/2 *Bohr/秒,呵呵
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